450x^2+1200x-600=0

Solution for 450x^2+1200x-600=0 equation:

450x^2+1200x-600=0

a = 450; b = 1200; c = -600;
Δ = b2-4ac
Δ = 12002-4·450·(-600)
Δ = 2520000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2520000}=\sqrt{360000*7}=\sqrt{360000}*\sqrt{7}=600\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1200)-600\sqrt{7}}{2*450}=\frac{-1200-600\sqrt{7}}{900}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1200)+600\sqrt{7}}{2*450}=\frac{-1200+600\sqrt{7}}{900}
$